Webarr = [], nonvalid = []; for (var j = 1; j < arr.length; j++) { if ( arr [j+1] <= arr [j] ) { nonvalid.push (j); } } Obviously the above algorightm checks only for values that are lower comparing the one before it. An array might contain values like these: arr = 1, 2, 3, 10, 5, 11, 12, 2, 4, 25 The non valid values are the bold ones. WebCreate one integer currentDigit. It will hold the rightmost digit of the number. Convert the num to num/10. Run one while loop to check for all digits of num. If any right digit is less than the left digit, mark flag as true and break from the loop. Else, change the rightmost digit to the next left digit and change the number to number / 10.

java - RegEx to check if the digits in a number are all the same …

Web26 jun. 2015 · If any adjacent numbers are not consecutive, we can return false. If it makes it all the way through, they all must be consecutive. Note that this also handles other than three numbers. For example, it always returns true if there's zero or one number passed. This may or may not be what you want. Web14 nov. 2015 · You are missing the first element of the array because of this code: int [] a = new int [args.length - 1] for (int i = 0; i springdale high school alumni

How to create a sequence of numbers in java - Stack Overflow

WebWrite a program that reads a sequence of integer numbers and outputs true if the sequence is ordered (in ascending or descending order), otherwise, false. Keep in mind, … WebGoing through the initial string, collect each contiguous sequence of digits and build its suffix tree. For your example it would look like (for the first 4 suffixes): R - root … Web25 sep. 2015 · Scanner x = new Scanner (System.in); int n; System.out.print ("Enter how many numbers to display"); n = x.nextInt (); int count = 0; int i = 1; while (count < n) { //is this right? if (count % 2 == 0) { System.out.print (i + " "); i += 2; } else { System.out.print (i + " "); i += 3; } count++; } Share Improve this answer Follow springdale high school basketball