WebSolution Verified by Toppr A 2=⎣⎢⎢⎡590−1−2−1 25−2⎦⎥⎥⎤ A 2−5A+4I=⎣⎢⎢⎡590−1−2−1 25−2⎦⎥⎥⎤−5⎣⎢⎢⎡221 01−1130⎦⎥⎥⎤+4⎣⎢⎢⎡100010001⎦⎥⎥⎤=⎣⎢⎢⎡−1−1−5−1−34 −3−102 ⎦⎥⎥⎤. therefore, X=⎣⎢⎢⎡115 13−4 310−2⎦⎥⎥⎤ Video Explanation Solve any question of … WebIf a and b are two unit vectors such that a+2b and 5a−4b are perpendicular to each other, then the angle between a and b is A 45 ∘ B 60 ∘ C cos −1(1/3) D cos −1(2/7) Medium Solution Verified by Toppr Correct option is B) Since the vectors a+2b+ and 5a−4b are perpendicular so (a+2b)⋅(5a−4b)=0 ⇒5∣a∣ 2+6a⋅b−8∣b∣ 2=0 ⇒6a⋅b=3(∣a∣=∣b∣=1)
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If a and b are two unit vectors such that a + 2b and 5a - Toppr
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